The period of a physical pendulum is 2pi √(I/mgd) , where I is the…
The period of a physical pendulum is 2pi √(I/mgd) , where I is the moment of inertia about the pivot point and d is the distance from the pivot point to the center of mass. A circular hoop hangs from a nail on a barn wall. The mass of the hoop is 3 kg and its radius is 20 cm. if it is displaced slightly by a passing breeze what is the period of the resulting oscillations? Option A. 1.3s is Correct. Explanation:
A. 1.3 s
B. 1.8 s
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Technifi Expert’s Answer:
Moment of inertia = mr2 + mr2
Moment of inertia = 2mr2
Time period = 2π (I/mgd)
Time period = 2π ( 2mr2/mgd)
Time period = 2π [( 2 x 0.22)/(9.8 x 0.2)]
Time period = 1.3 second
Option A. 1.3s is Correct.
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